Physics for Science & Engineering II
Physics for Science & Engineering II
By Yildirim Aktas, Department of Physics & Optical Science
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  • Introduction
  • Syllabus
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    • Chapter 01: Electric Charge
      • 1.1 Fundamental Interactions
      • 1.2 Electrical Interactions
      • 1.3 Electrical Interactions 2
      • 1.4 Properties of Charge
      • 1.5 Conductors and Insulators
      • 1.6 Charging by Induction
      • 1.7 Coulomb Law
        • Example 1: Equilibrium Charge
        • Example 2: Three Point Charges
        • Example 3: Charge Pendulums
    • Chapter 02: Electric Field
      • 2.1 Electric Field
      • 2.2 Electric Field of a Point Charge
      • 2.3 Electric Field of an Electric Dipole
      • 2.4 Electric Field of Charge Distributions
        • Example 1: Electric field of a charged rod along its Axis
        • Example 2: Electric field of a charged ring along its axis
        • Example 3: Electric field of a charged disc along its axis
        • Example 4: Electric field of a charged infinitely long rod.
        • Example 5: Electric field of a finite length rod along its bisector.
      • 2.5 Dipole in an External Electric Field
    • Chapter 03: Gauss’ s Law
      • 3.1 Gauss’s Law
        • Example 1: Electric field of a point charge
        • Example 2: Electric field of a uniformly charged spherical shell
        • Example 3: Electric field of a uniformly charged soild sphere
        • Example 4: Electric field of an infinite, uniformly charged straight rod
        • Example 5: Electric Field of an infinite sheet of charge
        • Example 6: Electric field of a non-uniform charge distribution
      • 3.2 Conducting Charge Distributions
        • Example 1: Electric field of a concentric solid spherical and conducting spherical shell charge distribution
        • Example 2: Electric field of an infinite conducting sheet charge
      • 3.3 Superposition of Electric Fields
        • Example: Infinite sheet charge with a small circular hole.
    • Chapter 04: Electric Potential
      • 4.1 Potential
      • 4.2 Equipotential Surfaces
        • Example 1: Potential of a point charge
        • Example 2: Potential of an electric dipole
        • Example 3: Potential of a ring charge distribution
        • Example 4: Potential of a disc charge distribution
      • 4.3 Calculating potential from electric field
      • 4.4 Calculating electric field from potential
        • Example 1: Calculating electric field of a disc charge from its potential
        • Example 2: Calculating electric field of a ring charge from its potential
      • 4.5 Potential Energy of System of Point Charges
      • 4.6 Insulated Conductor
    • Chapter 05: Capacitance
      • 5.01 Introduction
      • 5.02 Capacitance
      • 5.03 Procedure for calculating capacitance
      • 5.04 Parallel Plate Capacitor
      • 5.05 Cylindrical Capacitor
      • 5.06 Spherical Capacitor
      • 5.07-08 Connections of Capacitors
        • 5.07 Parallel Connection of Capacitors
        • 5.08 Series Connection of Capacitors
          • Demonstration: Energy Stored in a Capacitor
          • Example: Connections of Capacitors
      • 5.09 Energy Stored in Capacitors
      • 5.10 Energy Density
      • 5.11 Example
    • Chapter 06: Electric Current and Resistance
      • 6.01 Current
      • 6.02 Current Density
        • Example: Current Density
      • 6.03 Drift Speed
        • Example: Drift Speed
      • 6.04 Resistance and Resistivity
      • 6.05 Ohm’s Law
      • 6.06 Calculating Resistance from Resistivity
      • 6.07 Example
      • 6.08 Temperature Dependence of Resistivity
      • 6.09 Electromotive Force, emf
      • 6.10 Power Supplied, Power Dissipated
      • 6.11 Connection of Resistances: Series and Parallel
        • Example: Connection of Resistances: Series and Parallel
      • 6.12 Kirchoff’s Rules
        • Example: Kirchoff’s Rules
      • 6.13 Potential difference between two points in a circuit
      • 6.14 RC-Circuits
        • Example: 6.14 RC-Circuits
    • Chapter 07: Magnetism
      • 7.1 Magnetism
      • 7.2 Magnetic Field: Biot-Savart Law
        • Example: Magnetic field of a current loop
        • Example: Magnetic field of an infinitine, straight current carrying wire
        • Example: Semicircular wires
      • 7.3 Ampere’s Law
        • Example: Infinite, straight current carrying wire
        • Example: Magnetic field of a coaxial cable
        • Example: Magnetic field of a perfect solenoid
        • Example: Magnetic field of a toroid
        • Example: Magnetic field profile of a cylindrical wire
        • Example: Variable current density
    • Chapter 08: Magnetic Force
      • 8.1 Magnetic Force
      • 8.2 Motion of a charged particle in an external magnetic field
      • 8.3 Current carrying wire in an external magnetic field
      • 8.4 Torque on a current loop
      • 8.5 Magnetic Domain and Electromagnet
      • 8.6 Magnetic Dipole Energy
      • 8.7 Current Carrying Parallel Wires
        • Example 1: Parallel Wires
        • Example 2: Parallel Wires
    • Chapter 09: Induction
      • 9.1 Magnetic Flux, Fraday’s Law and Lenz Law
        • Example: Changing Magnetic Flux
        • Example: Generator
        • Example: Motional emf
        • Example: Terminal Velocity
        • Simulation: Faraday’s Law
      • 9.2 Induced Electric Fields
      • Inductance
        • 9.3 Inductance
        • 9.4 Procedure to Calculate Inductance
        • 9.5 Inductance of a Solenoid
        • 9.6 Inductance of a Toroid
        • 9.7 Self Induction
        • 9.8 RL-Circuits
        • 9.9 Energy Stored in Magnetic Field and Energy Density
      • Maxwell’s Equations
        • 9.10 Maxwell’s Equations, Integral Form
        • 9.11 Displacement Current
        • 9.12 Maxwell’s Equations, Differential Form
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Online Lectures » Chapter 04: Electric Potential » 4.2 Equipotential Surfaces » Example 2: Potential of an electric dipole

Example 2: Potential of an electric dipole

from Office of Academic Technologies on Vimeo.

Example 2- Potential of an electric dipole

Let’s calculate the potential of an electric dipole. Potential of an electric dipole.

As you recall, dipole is a point charge system which consists of two point charges with equal magnitudes and opposite signs, separated from one another by a very small distance. Let’s say we’re interested with the potential of such a system at a certain distance, r, away from the center of a dipole. Let’s say the distance between the positive charge and the point of interest is r+, and the distance between the negative charge and the point of interest is denoted with r-.

As you see, I’m not drawing any vectors, no directions, because I’m dealing with potential and potential is a scaler quantity. It’s not a vectoral quantity. It doesn’t have any directional properties. It is just electric potential energy per unit charge, and those two quantities are all scalers.

Well, to be able to calculate the potential of this system, we will first calculate the potential of each one of these charges at the point of interest, so V1 is going to be equal to the potential of a point charge is the charge divided by 4π ε0 times its distance to the point of interest, and that is r+ for this charge. Let’s call this one as V+. And for the negative charge, V-, we will have –q over 4π ε0 r-.

Total potential is the direct sum of these two scaler quantities, V+ plus V-, and therefore, V will be equal to, if we add these two quantities we will have q over 4π ε0 r+, and the other one is minus, so –q over 4π ε0 r-. We can write it in more compact form by taking common quantities parenthesis, which is in this case, q, in the numerator, and 4π ε0 in the denominator. This will be multiplied by 1 over r+ and minus 1 over r-.

Let’s go ahead and have common denominator in the parenthesis. Therefore, the potential will be equal to q over 4π ε0, r– minus r+ divided by r+ times r-. And this will be, basically, the answer. Knowing the distances of r– and r+ and the magnitude of the dipole, we can easily calculate the potential that it generates at that location.

Here now we’re going to look at an approximate case.  Let’s denote this angle as θ, which is the angle that r is making with the dipole, and we will look at a special case and that is the case of that the point of interest’s distance to the dipole, which is r, is much, much greater than the dipole separation distance d. If this is the case, then we can visualize these three lines almost to be parallel to one another, and this angle being approximately equal to θ. If we just draw a line, or take the projection of this point along r-, then this distance is going to be equal to r– minus r+.

Furthermore, if this angle is approximately equal to θ, as you can see, we end up with formation of a right triangle over here, with this angle being 90 degrees, and the hypotenuse of this triangle is the dipole separation distance, d. In that case, r– minus r+, which is this distance, becomes approximately equal to d times cosine of θ.

Furthermore, for such a point which is very, very far away from the dipole in comparing to the separation distance, we can also approximately assume that these three distances are about the same. So we can write these expressions for r much, much greater than d distance as r– minus r+ is equal to, approximately equal to d cosine of θ, and r-, which is approximately equal to r+ and that is approximately equal to r.  In that case, r– r plus approximately becomes equal to r2.

This enables us to write down this approximate expression for this specific case, and the potential becomes q over 4π ε0. So instead of r– minus r+, we will have d cosine of θ, and in the denominator, r– times r+ will give us approximately r2.

As you recall, when we were calculating the electric field of a dipole, we said that the charge of the dipole, the magnitude of the charge of the dipole, and the separation distance, d, these are unique properties of the specific dipole, and we had a special name for this product.  We called it “magnitude of the electric dipole moment vector”, and we denoted this with P. In terms of electric dipole moment vector magnitude, then the potential can be expressed as P times cosine of θ over 4π ε0 r2.

When we look at this expression, we see that it takes its maximum and minimum value, depending upon this angle, θ, which is basically the orientation of this point, P, relative to the dipole, and we can easily see that for θ is equal to 90 degrees, cosine of 90 is 0, and this corresponds to the equatorial plane. And the potential of the dipole becomes equal to 0 for this case. That can be interpreted as charge lying on this plane always equidistant from the positive and the negative charges which make up the dipole so that the scaler potentials set up by each charge cancel each other.

Therefore, if you consider the equatorial plane, which is the plane passing through the center of the dipole, this plane, and perpendicular to the dipole, every point on this plane will be equidistant away from the positive charge and the negative charge, and the positive charge’s potential, therefore, will cancel with the negative charge’s potential because they’re going to be the same distance away to every point on this plane.

Another thing that we can conclude by looking at this example, since the positive charge’s potential is q over 4π ε0 r and the negative charge’s is q over –q over 4π ε0 r, therefore, if these two charges are same distance away to the point of interest, since positive is greater than negative, the potential associated with the positive charge is greater than the potential associated with the negative charge. But when we add these two, they will cancel one another on the equatorial plane of this dipole.

By the same token, we can see that when θ is equal to 0 degrees, and that is point along the dipole axis basically here to the positive charge, then the potential becomes P over 4π ε0 r2, since cosine of 0 is just 1. For θ is equal to 180 degrees, now we are near to the negative charge along the axis, then the potential is going to be –P over 4π ε0 r2 since cosine of 180 degrees is equal to -1. If we go back and look at our diagram then, when the angle θ is 0, we’re talking about along the axis of the dipole, the 0 will correspond to the points near to the positive charge, we end up with the net positive potential. For θ is equal to 180 degrees, now we are talking about near to the negative charge side along the axis, and then the net potential in that case is going to be negative, because the negative charge will be nearer to the point of interest relative to the positive charge.

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